Home
Class 12
PHYSICS
The thermo emf of a thermocouple is 40 m...

The thermo emf of a thermocouple is `40 mu V K^(-1)` at room temperature. A galvanometer of resistance `100 Omega` capable of detecting current as law as `10 muA` is connected with one such thermocouple. Calculate the smallest temperature difference that can be detected by such a thermocouple.

Text Solution

Verified by Experts

The correct Answer is:
25 K
Promotional Banner

Topper's Solved these Questions

  • THERMOELECTRICITY

    SL ARORA|Exercise Problem|2 Videos
  • SOLIDS AND SEMICONDUCTOR DEVICES

    SL ARORA|Exercise PROBLEM_TYPE|9 Videos
  • TRANSIENT CURRENT

    SL ARORA|Exercise Type D|13 Videos

Similar Questions

Explore conceptually related problems

The thermo e.m.f. of a thermo- couple is 25 muV//^@C at room temperature. A galvanometer of 40 ohm resistance, capable of detecting current as low as 10^(-5) A, is connected with the thermo couple. The smallest temperature difference that can be detected by this system is

Near room temperature , the thermo emf of a thermo couple is 40 muV per degree. A galvanometer of 25 Omega and capable of detecting current of the order of 4 mu A is used. Calcualate the smallest temperature difference that can be detected with this galvanometer.

The themo emf of a copper-constantan thermocouple is 40muV.^(@)C^(-1) at room temperature. A galvanometer whose resistance is 80 Omega and current sensitivity 1 muA is used. Find the smallest temperature difference that the galvanometer can detect.

A thermocouple of negligible resistance produces an emf fo 40 mu V//^(@)C in the linear range of temperature. A galvanometer of resistance 10 Omega whose sensitivity is 1 mu A//div is employed with the thermocouple. The smallest value of temperature difference that can be detected by the system will

A galvanometer of internal resistance 100 Omega has a full scale deflection current of 1mA. To convert it into a voltmeter of range 0-10V, the resistance to be connected is

A galvanometer of internal resistance 100 Omega has a full scale deflection current of 1mA . To convert it into a voltmeter of range 0-10V , the resistance to be connected is

A galvanometer of resistance 100 Omega gives the full scale deflection for a current of 10 m A. If a resistance of 1 Omega is connected in parallel to the coil of the galvanometer , then maximum current that can be measured with the galvanometer will be

When a battery of emf 2 V is directly connected to a galvanometer of resistance 100 Omega . It shows full scale deflection. To measure 1 A current , the shunt must be

A galvanometer of resistance 10Omega shows full scale deflection for current 100 mA. The resistance that needs to be connected in series with the galvanometer so that it can be used to measure potential difference in the range 0-100 V is (in Ohm):

A galvanometer has resistance 100 Omega and it requires current 100 muA for full scale deflection. A resistor 0.1 Omega is connected to make it an ammeter. The smallest current required in the circuit to produce the full scale deflection is