Home
Class 12
PHYSICS
Calculate the coefficient of self indu...

Calculate the coefficient of self induction of a soleined of 500 turns when a current of 1.25 A produce a magnetic flux of one microweber.
[Hint : See exerices 5]

Text Solution

Verified by Experts

The correct Answer is:
0.4 ml
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    NN GHOSH|Exercise EXERICISES-B|18 Videos

  • ELECTROMAGNETIC INDUCTION

    NN GHOSH|Exercise EXERICISES-B|18 Videos

  • ELECTRIC FIELD AND POTENIAL

    NN GHOSH|Exercise EXERCISE-B|35 Videos

  • FUNDAMENTAL OF CURRENT ELECTRICITY

    NN GHOSH|Exercise Exercises|45 Videos

Similar Questions

Explore conceptually related problems

What will be the self inductance of a coid of 100 turns if a current of 5 A produces a magnetic flux 5xx10^(-5) Wb?

The self inductance of the coil of 100 turns, in which a current of 4A produces a flux of 40 Wb is

Calculate the coefficient of self induction of a soleined of 500 turns and a length of 1 m . The area of cross-section is 7 cm^(2) and permeability to the core is 1000.

A coil of 100 turns carries a current of 5mA and creates a magnetic flux of 10^(-5) weber. The inductance is

A coil of 100 turns with a current of 5A produce a magnetic flux of 1 mu Wb and each turn of the coil. The coefficeint of self induction is

Calculate the self-inductance of a coil of 100 turns, if a current of 2A gives rise to magnetic flux of 50muWb through the coil. Also calculate the magentic energy stored in the medium surrounding the coil for the above value of current.

The self inductance of a closely wound coils of 100 turns is 5 mH . What is the flux throught the coil when the current in it is 10 mA ? [Hint : See exerices 5]