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if f(2)=4,f'(2)=1 then lim(x->2){xf(2)-2...

if `f(2)=4,f'(2)=1` then `lim_(x->2){xf(2)-2f(x)}/(x-2)`

A

1

B

2

C

3

D

-2

Text Solution

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The correct Answer is:
B
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