Bromination of alkane is initiated by a process of

Options

A. Pyrolysis
B. Substitution
C. Homolysis
D. Peroxidation

Explanation

To answer the question about how bromination of an alkane is initiated, we can break down the process into clear steps:

### Step-by-Step Solution:

1. **Understanding Bromination**: Bromination of alkanes is a type of halogenation reaction where bromine (Br2) reacts with an alkane to form alkyl bromides. This reaction involves several steps, and we need to identify the initiation step.

2. **Mechanism of Bromination**: The bromination process can be divided into three main steps:
- **Initiation**
- **Chain Propagation**
- **Termination**

3. **Initiation Step**: The initiation step involves the breaking of the Br-Br bond in the bromine molecule (Br2). This bond cleavage occurs through a process called **homolysis**, where each bromine atom takes one electron from the bond, resulting in the formation of two bromine radicals (Br•).

4. **Formation of Bromine Radicals**: The homolysis of bromine can be represented as:
\[ \text{Br}_2 \xrightarrow{\text{UV light or heat}} 2 \text{Br}• \]
Here, the energy (from UV light or heat) is required to break the bond between the two bromine atoms.

5. **Conclusion**: The initiation of bromination of alkanes is thus characterized by the homolytic cleavage of the bromine molecule, leading to the formation of bromine radicals. This is the first step that allows the bromination process to proceed.

### Final Answer:
The bromination of alkane is initiated by a process of **homolysis**.

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