Which of following is a correct set

Options

A. Graphite, `SP^(2)`
B. Diamond, `SP^(2)`
C. Graphite, `SP^(3)`
D. Diamond, SP

Answer

To determine the correct set of hybridization for graphite and diamond, we need to analyze the hybridization states of carbon in both materials.

### Step-by-Step Solution:

1. **Understanding Graphite Structure**:
- Graphite consists of carbon atoms arranged in layers of hexagonal sheets.
- Each carbon atom in graphite is bonded to three other carbon atoms.
- The bonding involves one sigma bond and two pi bonds, which allows for delocalization of electrons.

2. **Determining Hybridization of Graphite**:
- Since each carbon atom in graphite is bonded to three other carbon atoms, it undergoes **sp² hybridization**.
- This means that one s orbital and two p orbitals mix to form three sp² hybrid orbitals, which are arranged in a plane.

3. **Understanding Diamond Structure**:
- Diamond has a three-dimensional tetrahedral structure.
- Each carbon atom in diamond is bonded to four other carbon atoms.

4. **Determining Hybridization of Diamond**:
- In diamond, each carbon atom forms four sigma bonds with four neighboring carbon atoms, leading to **sp³ hybridization**.
- This involves mixing one s orbital and three p orbitals to form four sp³ hybrid orbitals, which are arranged tetrahedrally.

5. **Summarizing Hybridizations**:
- For graphite: **sp² hybridization**.
- For diamond: **sp³ hybridization**.

6. **Identifying the Correct Set**:
- Based on the analysis, the correct set of hybridizations is:
- Graphite: sp²
- Diamond: sp³

### Conclusion:
The correct set of hybridizations for graphite and diamond is:
- Graphite: sp²
- Diamond: sp³