The figure shows elliptical orbit of a plant P about the sun S. The shaded area CSD is twice tha shaded area ASB. If `t_(1)` is the time taken by the planet to move from C to D and `t_(2)` is the time to move from A to B, determine the ratio `t_(1)//t_(2)`

Explanation

According to Kepler's second law, the areal velocity of the planet remains constant
`:. (A_(1))/(t_(1))=(A_(2))/(t_(2))`
`:. (t_(1))/(t_(2))=(A_(1))/(A_(2))=("Area CSD")/("Area ASD")=2 rArr t_(1)=2t_(2)`