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Two particles of equal mass m(0) are mov...

Two particles of equal mass `m_(0)` are moving round a circle of radius r due to their mutual gravitational interaction. Find the time period of each particle.

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To find the time period of each particle in a system where two particles of equal mass \( m_0 \) are moving in a circular path due to their mutual gravitational interaction, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the System**: - We have two particles, each of mass \( m_0 \), moving in a circular path with radius \( r \). - The gravitational force between the two particles provides the necessary centripetal force for their circular motion. ...
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DC PANDEY-GRAVITATION-(C) Chapter Exercises
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  15. According to Kepler's law of planetary motion, if T represents time pe...

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  16. If mass of a body is M on the earth surface, then the mass of the same...

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  17. Two spherical bodies of masses m and 5m and radii R and 2R respectivel...

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  18. The force of gravitation is

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  19. Dependence of intensity of gravitational field (E) of earth with dista...

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  20. Keeping the mass of the earth as constant, if its radius is reduced to...

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