Assume that if the earth were made of lead of relative density 11.3, then what would be the value of acceleration due to gravity on the earth surface ?

Explanation

Since, density of earth can be given as
`rho=` Relative density `xx` density of water `=11.3 xx 10^(3) "kgm"^(-3)`
`:.` Acceleration due to gravity on the earth's surface,
`g=(GM)/(R^(2))=(G)/(R^(2)).(4)/(3)piR^(3).rho`
`=(4)/(3)xx(22)/(7)xx6.67xx10^(-11)xx6.4 xx10^(6)xx11.2xx10^(3)`
`=22.21 ms^(-2)`