Mass of 10 kg is distributed uniformly over a ring of radius 1m. Find the gravitational potential at a point lies on the axis of the ring at a distance of 1m from the centre.

Explanation

Mass of the ring, `M=1` kg
Radius of the ringm `R=1` m
Distance of the point, `r=1` m
`:.` Required gravitational potential
`V(r=1)=(-GM)/(sqrt(R^(2)+r^(2)))=(-Gxx1)/(sqrt((1)^(2)+(1)^(2)))`
`=(-G)/(sqrt(2))=(-6.67xx10^(-11))/(sqrt(2))"Jkg"^(-1)=-4.716xx10^(-11)"Jkg"^(-1)`.