Calculate the escape velocity from the surface of a planet of mass `14.8 xx 10^(22)` kg. It is given that radius of the planet is `3.48 xx 10^(6)` m.

Explanation

Given, mass of planet `M_(p) = 14.8 xx 10^(22)` kg
Radius of the planet `R_(p) = 3.48 xx 10^(6)` m. Escape velocity from the surface of planet is
`v_(e)=sqrt((2GM_(p))/(R_(p)))`
Substituting the values, we have
`v_(e)=sqrt((2xx6.67xx10^(-11)xx14.8xx10^(22))/(3.48xx10^(6)))`
`=2.4xx10^(3) "ms"^(-1) or 2.4 "kms"^(-1)`.