A particle is projected from the surface of earth with intial speed of 4 km/s. Find the maximum height attained by the particle. Radius of earth = 6400 km and `g = 9.8 m//s^(2)`

Explanation

The maximum height attained by the particle is,
`h=(v^(2))/(2g-(v^(2))/(R))`
Substituting the values, we have
`h=((4xx10^(3))^(2))/(2xx9.8-((4.0xx10^(3))^(2))/(6.4xx10^(6)))=9.35xx10^(5) "m" or f~~ 9.35 "km"`.