A simple pendulum has a time period `T_(1)` when on the earth's surface and `T_(2)` when taken to a height R above the earth's surface, where R is the radius of the earth. The value of `(T_(2))/(T_(1))` is

Options

A. 1
B. `sqrt(2)`
C. 4
D. 2

Answer

D

Explanation

As, `T=2pisqrt((l)/(g))prop(1)/(sqrt(9))`
`:. (T_(2))/(T_(1))=sqrt((g_(1))/(g_(2)))=sqrt((g)/((g)/((1+h//R)^(2))))=2" "("at h=R")`.