The escape velocity of a body projected vertically upward from the earth's surface is `11.2 " kms"^(-1)` . If the body is projected in a direction making `30^(@)` angle to the vertical, its escape velocity in this case will be

Options

A. `11.2 " kms"^(-1)`
B. `(11.2)/(2) " kms"^(-1)`
C. `11.2 xx (sqrt(3))/(2) "kms"^(-1)`
D. `(11.2)/(3)"kms"^(-1)`

Answer

A

Explanation

Escape velocity is independent of angle at which particle is projected. Therefore when the body is projected in direction making `30^(@)` angle to the vertical, then its escape velocity will remain same, i.e., `11.2 "kms"^(-1)`