A satellite is revolving round the earth with orbital speed `v_(0)` if it is imagined to stop suddenly the speed with which it will strike the surface of the earth would be `(v_(e)` - escape speed of a body from earth s surface)

Options

A. `(v_(e)^(2))/(v_(o))`
B. `2v_(o)`
C. `sqrt(v_(e)^(2)-v_(o)^(2))`
D. `sqrt(v_(e)^(2)+2v_(o)^(2)`

Answer

D

Explanation

`U_(2)=2((1)/(2)mv_(0)^(2))`

Now, `(1)/(2)mv^(2)=-U_(2)+U_(1)=U_(1)-U_(2)=(mv_(e)^(2))/(2)0\-mv_(e)^(2)`
`:. v=sqrt(v_(e)^(2)-2v_(o)^(2))`