Two concentric spherical shells are as shown in figure. Match the following columns

`{:(,"Column-I",,"Column-II"),("(A)","Potential at A","(p)","greater than B"),("(B)","Gravitational field at A","(q)","less than B"),("(C)","As one moves from C to D","(r)","Potential remains constant"),("(D)","As one moves from D to A","(s)","Gravitational field decreases"),(,,"(t)","None"):}`

Answer

`(A rarr q,B rarr t,C rarr r,D rarr s)`

Explanation

Inside a shell gravitational potential `V = -(GM)/(R)`= constant
And gravitational field intensity E = 0
Outside the shell, `V=-(GM)/(r) and E=(GM)/(r^(2))`
As `r` increase, `V=-(GM)/(r) and E=(GM)/(r^(2))`
As `r` increase, V increase and E decreases
Therefore, potential at A. will be less than B. Gravitational field inside the shell will be zero. As one moves from C and D. the gravitational potential remains constant adn when one moves from D to A. gravitational field decreases.