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The value of acceleration due to gravity...

The value of acceleration due to gravity at the surface of earth

A

is maximum at the poles

B

is maximum at the equator

C

remains constant everywhere on the surface of the earth

D

is maximum at the international time line

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To find the value of acceleration due to gravity at the surface of the Earth and determine where it is maximum, we can follow these steps: ### Step 1: Understand the Formula for Acceleration Due to Gravity The acceleration due to gravity (g) at the surface of the Earth can be calculated using the formula: \[ g = \frac{GM}{R^2} \] Where: - \( G \) is the universal gravitational constant, - \( M \) is the mass of the Earth, - \( R \) is the radius of the Earth. ### Step 2: Analyze the Radius at Different Locations The Earth is not a perfect sphere; it is slightly oblate. This means that the radius at the equator (\( R_e \)) is greater than the radius at the poles (\( R_p \)). Specifically, we can say: \[ R_e > R_p \] ### Step 3: Compare the Values of g at the Poles and Equator Since \( g \) is inversely proportional to the square of the radius (\( R^2 \)), we can conclude: - At the poles, where the radius is the smallest (\( R_p \)), the value of \( g \) will be the largest. - At the equator, where the radius is larger (\( R_e \)), the value of \( g \) will be smaller. ### Step 4: Conclusion From the analysis above, we can conclude that: - The acceleration due to gravity is maximum at the poles and minimum at the equator. - Therefore, the correct answer to the question is that the value of acceleration due to gravity is maximum at the poles. ### Final Answer The acceleration due to gravity at the surface of the Earth is maximum at the poles. ---

To find the value of acceleration due to gravity at the surface of the Earth and determine where it is maximum, we can follow these steps: ### Step 1: Understand the Formula for Acceleration Due to Gravity The acceleration due to gravity (g) at the surface of the Earth can be calculated using the formula: \[ g = \frac{GM}{R^2} \] Where: - \( G \) is the universal gravitational constant, - \( M \) is the mass of the Earth, ...
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  11. Two identical thin ring each of radius R are co-axially placed at a di...

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  12. If r is the distance between the Earth and the Sun. Then, angular mome...

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  14. A geostationary satellite is orbiting the earth at a height of 5R abov...

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  15. When a satellite is moving around the earth with velocity v, then to m...

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  16. A lauching vehicle carrying an artificial satellite of mass m is set f...

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  17. Consider a satellite orbiting the earth as shown in the figure below. ...

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  18. A body is projected vertically upwards from the surface of the earth w...

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