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An object is placed at a distance of 15 ...

An object is placed at a distance of 15 cm from a convex mirror and images is formed at a distance of 5 cm from the mirror. Calculate the radius of curvature of the mirror.

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To solve the problem, we will use the mirror formula and the relationship between the focal length and the radius of curvature for a convex mirror. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Object distance (u) = -15 cm (The object distance is negative for a convex mirror) - Image distance (v) = +5 cm (The image distance is positive for a convex mirror) 2. **Use the Mirror Formula:** The mirror formula is given by: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] Where \( f \) is the focal length of the mirror. 3. **Substitute the Values into the Mirror Formula:** \[ \frac{1}{f} = \frac{1}{5} + \frac{1}{-15} \] 4. **Calculate the Right Side:** - Find a common denominator for the fractions: \[ \frac{1}{5} = \frac{3}{15} \quad \text{and} \quad \frac{1}{-15} = -\frac{1}{15} \] - Therefore, \[ \frac{1}{f} = \frac{3}{15} - \frac{1}{15} = \frac{2}{15} \] 5. **Find the Focal Length (f):** - Taking the reciprocal gives: \[ f = \frac{15}{2} \text{ cm} = 7.5 \text{ cm} \] 6. **Calculate the Radius of Curvature (R):** The radius of curvature \( R \) is related to the focal length by the formula: \[ R = 2f \] - Substituting the value of \( f \): \[ R = 2 \times \frac{15}{2} = 15 \text{ cm} \] ### Final Answer: The radius of curvature of the convex mirror is **15 cm**. ---
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