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A needle 10 cm long is placed along the ...

A needle 10 cm long is placed along the axis of a convex lens of focal length 10 cm such that the middle point of the neddle is at a distance of 10 cm from the lens. Find the length of the image of the neddle.

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To find the length of the image of a needle placed along the axis of a convex lens, we will follow these steps: ### Step 1: Understand the setup - We have a needle that is 10 cm long. - The middle point of the needle is placed 10 cm away from the lens. - The focal length of the convex lens is also 10 cm. ### Step 2: Determine the positions of the ends of the needle - Since the needle is 10 cm long, if the middle point is at 10 cm from the lens, the ends of the needle will be: - Point A (one end) is at \(10 \, \text{cm} - 5 \, \text{cm} = 5 \, \text{cm}\) from the lens. - Point B (the other end) is at \(10 \, \text{cm} + 5 \, \text{cm} = 15 \, \text{cm}\) from the lens. ### Step 3: Use the lens formula to find the image positions The lens formula is given by: \[ \frac{1}{V} - \frac{1}{U} = \frac{1}{F} \] Where: - \(V\) is the image distance, - \(U\) is the object distance (negative for real objects), - \(F\) is the focal length. #### For Point A: - The object distance \(U_A = -5 \, \text{cm}\) (since it's on the same side as the object). - The focal length \(F = 10 \, \text{cm}\). Using the lens formula: \[ \frac{1}{V_A} = \frac{1}{U_A} + \frac{1}{F} \] \[ \frac{1}{V_A} = \frac{1}{-5} + \frac{1}{10} \] \[ \frac{1}{V_A} = -\frac{2}{10} + \frac{1}{10} = -\frac{1}{10} \] \[ V_A = -10 \, \text{cm} \] #### For Point B: - The object distance \(U_B = -15 \, \text{cm}\). Using the lens formula: \[ \frac{1}{V_B} = \frac{1}{U_B} + \frac{1}{F} \] \[ \frac{1}{V_B} = \frac{1}{-15} + \frac{1}{10} \] \[ \frac{1}{V_B} = -\frac{2}{30} + \frac{3}{30} = \frac{1}{30} \] \[ V_B = 30 \, \text{cm} \] ### Step 4: Calculate the length of the image The length of the image of the needle is given by the distance between the images of points A and B: \[ \text{Length of image} = |V_B - V_A| = |30 - (-10)| = |30 + 10| = 40 \, \text{cm} \] ### Conclusion The length of the image of the needle is \(40 \, \text{cm}\). ---
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