Home
Class 11
PHYSICS
In a hypothetical concept, electron of m...

In a hypothetical concept, electron of mass `m_(e)` revolves around nucleus due to gravitational force of attraction between electron and proton of mass `m_(p)`. If the radius of circular path of electron is r, then the speed of electron is

A

`sqrt(((Gm_(p)m_(e))/(4r)))`

B

`sqrt(((Gm_(p)m_(e))/(r)))`

C

`sqrt(((Gm_(p))/(r)))`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    BITSAT GUIDE|Exercise BITSAT Archives|15 Videos
  • ELASTICITY

    BITSAT GUIDE|Exercise BITSAT ARCHIVES|9 Videos
  • HEAT, TEMPERATURE AND CALORIMETRY

    BITSAT GUIDE|Exercise Bitsat archives|9 Videos

Similar Questions

Explore conceptually related problems

Why do the electrons revolve around the nucleus?

Why is electron supposed to be revolving around the nucleus?

The force of attraction between an electron revolving around the nucleus and the nucleus is ______ force.

The angular speed of an electron revolving around the H-nucleus is proportional to

A particle of mass m is located inside a spherical shell of mass M and radius R. The gravitational force of attraction between them is

The acceleration of electron due to mutual attraction between electron and a proton when they are 1.6 Angstroms apart is

If an electron of charge (-e) and mass m_(e) revolves around the nucleus of an atom having magnetic moment M_(e) , then angular momentum of electron is