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In order to make the weight of a 5kg bod...

In order to make the weight of a 5kg body to zero at the equator. The angular speed of the earth would must be (take, `g = 10m//s^(2)` and radius of the earh, `R = 6400 km)`

A

`0.00125 rad s^(-1)`

B

`0.0125 rad s^(-1)`

C

`0.125 rad s^(-1)`

D

`0.0325 rad s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
As `g' = g - omega^(2)R cos^(2)phi`
At the equator, `phi = 0`, i.e., `cos phi =1`
For weight to be zero `g' = 0`
`:. omega = sqrt((g)/(R)) = 0.00125 rads^(-1)`
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