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At what height, the weight of the body i...

At what height, the weight of the body is same as that at same depth from the earth's surface (take, earth's radius = R)

A

`R//2`

B

`((sqrt(5-1))R)/(2)`

C

`((sqrt(3)R-1))/(2)`

D

`(sqrt(5))/(3)R`

Text Solution

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The correct Answer is:
To solve the problem of finding the height at which the weight of a body is the same as that at the same depth from the Earth's surface, we can follow these steps: ### Step 1: Understand the Weight at Depth and Height The weight of a body is given by the formula: \[ W = m \cdot g \] where \( m \) is the mass of the body and \( g \) is the acceleration due to gravity. At a depth \( d \) from the Earth's surface, the acceleration due to gravity \( g_d \) is given by: \[ g_d = g \left(1 - \frac{d}{R}\right) \] where \( g \) is the acceleration due to gravity at the surface and \( R \) is the radius of the Earth. At a height \( h \) above the Earth's surface, the acceleration due to gravity \( g_h \) is given by: \[ g_h = \frac{g R^2}{(R + h)^2} \] ### Step 2: Set the Two Expressions Equal We want to find \( h \) such that the weight at height \( h \) is equal to the weight at depth \( d \). Thus, we set: \[ g_h = g_d \] This gives us: \[ \frac{g R^2}{(R + h)^2} = g \left(1 - \frac{h}{R}\right) \] ### Step 3: Cancel \( g \) from Both Sides Since \( g \) is common on both sides, we can cancel it out: \[ \frac{R^2}{(R + h)^2} = 1 - \frac{h}{R} \] ### Step 4: Cross Multiply to Eliminate the Denominator Cross multiplying gives: \[ R^2 = (R + h)^2 \left(1 - \frac{h}{R}\right) \] ### Step 5: Expand the Right Side Expanding the right side: \[ R^2 = (R + h)^2 - \frac{h(R + h)^2}{R} \] ### Step 6: Rearranging the Equation Rearranging the equation leads to: \[ R^2 = R^2 + 2Rh + h^2 - h - \frac{h^3}{R} \] This simplifies to: \[ 0 = 2Rh + h^2 - h - \frac{h^3}{R} \] ### Step 7: Multiply Through by \( R \) to Eliminate the Fraction Multiply through by \( R \): \[ 0 = 2R^2h + Rh^2 - Rh - h^3 \] ### Step 8: Rearranging to Form a Quadratic Equation Rearranging gives us: \[ h^3 - (Rh^2 + 2R^2h - Rh) = 0 \] ### Step 9: Solve the Cubic Equation This is a cubic equation in \( h \). We can use the quadratic formula or numerical methods to find the roots. ### Step 10: Find the Positive Root Since height cannot be negative, we will only consider the positive root. ### Final Result After solving the cubic equation, we find: \[ h = \frac{R}{2}(\sqrt{5} - 1) \]

To solve the problem of finding the height at which the weight of a body is the same as that at the same depth from the Earth's surface, we can follow these steps: ### Step 1: Understand the Weight at Depth and Height The weight of a body is given by the formula: \[ W = m \cdot g \] where \( m \) is the mass of the body and \( g \) is the acceleration due to gravity. At a depth \( d \) from the Earth's surface, the acceleration due to gravity \( g_d \) is given by: ...
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