The change in the gravitational potential energy when a body of a mass `m` is raised to a height `nR` above the surface of the earth is (here `R` is the radius of the earth)

Options

A. nmgR
B. `mgR = ((n^(2)+1)/(n^(2)))`
C. `mgR ((n-1)/(n))`
D. `mgR ((n+1)/(n))`

Answer

C

Explanation

Change in `PE = DeltaU = U_(t) - U_(i) = GmM ((1)/(R)-(1)/(nR))`
`= (GMm)/(R) ((n-1)/(n)) = mgR ((n-1)/(n)) ( :' g = (Gm)/(R^(2)))`