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A satellite is orbiting closely to earth...

A satellite is orbiting closely to earth and having kinetic energy K. the kinetic energy required by it to just overcome the gravitational pull of the earth, is

A

2K

B

`sqrt(2)K`

C

`sqrt(3)K`

D

`2sqrt(2)K`

Text Solution

Verified by Experts

The correct Answer is:
A
Orbital speed closer to the earth is `sqrt(gR)`.
`K = KE =(1)/(2)m(sqrt(gR))^(2) = (mgR)/(2)`
Now, if the velocity is charged to `sqrt(2gR)` (escape spped), then the kinetic energy K' will be ltbr? `K' = (1)/(2)m (sqrt(2gR))^(2) = mgR`
`K' = (1)/(2)m (sqrt(2gR))^(2) = mgR`
`rArr K' = 2k`
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