Home
Class 11
PHYSICS
If M is the mass of the earth and R its ...

If `M` is the mass of the earth and `R` its radius, the ratio of the gravitational acceleration and the gravitational constant is

A

`(R^(2))/(M)`

B

`(M)/(R^(2))`

C

`MR^(2)`

D

`(M)/(R)`

Text Solution

Verified by Experts

The correct Answer is:
B

Gravitational acceleration is given by `g = (GM)/(R^(2))`
where, `G =` gravitational constant
`(g)/(G) = (M)/(R^(2))`
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    BITSAT GUIDE|Exercise BITSAT Archives|15 Videos
  • ELASTICITY

    BITSAT GUIDE|Exercise BITSAT ARCHIVES|9 Videos
  • HEAT, TEMPERATURE AND CALORIMETRY

    BITSAT GUIDE|Exercise Bitsat archives|9 Videos

Similar Questions

Explore conceptually related problems

If M is the mass of the earth and R its radius, then ratio of the gravitational acceleration and the gravitational constant is

If M is the mass of the earth and R its radius, the radio of the gravitational acceleration and the gravitational constant is

The value of gravitational acceleration at a height equal to radius of earth, is

universal gravitational constant and gravitational acceleration of the earth.

If M be the mass of the earth, R its radius (assumed spherical) and G gravitational constant, then the amount of work that must be done on a body of mass m, so that it completely escapes from the gravity of the earth of the earth is given by

Universal gravitational constant and gravitational acceleration of the earth .

The kinetic energy needed to project a body of mass m from the earth's surface to infinity is (R is radius of the earth, g is gravitational acceleration on the surface of the earth)

The escape velocity of an object from the earth depends upon the mass of the earth ( M ), its mean density (rho) , its radius ( R ) and the gravitational constant ( G ). Thus the formula for escape velocity is