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The temperature of an iron piece is heat...

The temperature of an iron piece is heated from `30^@ C "to" 90^@ C`. What is the change in its temperature on the fahrenheit scale and on the kelvin scale?

A

`108^(@)`, 60K

B

`100^(@)`F, 55 K

C

`100^(@)`F, 65K

D

`60^(@)`F, 108 K

Text Solution

Verified by Experts

a) `DeltaT_(c)=90^(@)-30^(@)`C=`60^(@)`C
`DeltaT_(F) = 9/5DeltaT_(C) = 9/5(60^(@)) = 108^(@)`F
`DeltaT = DeltaT_(c)=60K`
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