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The motor heat capacity of rock salt at ...

The motor heat capacity of rock salt at low temperatures varies with temperatures according to Debye's `T_(3)` law.
Thus, C = `kT^(3)/theta^(3)`, where k = 1940 J`mol^(-1)Ko^(-1)`, `theta` = 281 K)
Calculate how much heat is required to raise the tempratures of 2 moles of rock salt from 10 K to 50 K?

A

800 J

B

373 J

C

273 J

D

None of these

Text Solution

Verified by Experts

c) dQ = nCdt, dQ= nk`(T^(3)/(theta^(3))dT)`
`theta=(nk)/(theta^(3))int_(T_(1))^(T_(2)) T^(3)dt = (nk)/(theta^(3))((T_(2)^(4)-T_(1)^(4))/4)`
`=(2xx1940(50^(4)-10^(4)))/((282)^(3)xx 4)=272.79 J rArrQ=273J`
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