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1 g of water (volume 1 cm^(3) becomes 16...

1 g of water (volume 1 `cm^(3)` becomes 1671 `cm^(3)` of steam when boiled at a pressure of 1atm. The latent heat of vaporisation is 540 cal/g, then the external work done is (1 atm `= 1.013 xx 10^(5)` N/`m^(2))`

A

499.7 J

B

40.3 J

C

169.2 J

D

128.57 J

Text Solution

Verified by Experts

c) Work done , `W= pDeltaV= 1.013 xx 10^(5) xx (1671 -1) xx 10^(-6)`
`=(1.013 xx 10^(5) xx 1670 xx 10^(-6)`= 169.2 J
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