A light rod of length L is suspended from a support horizonatlly by means of two vertical wires A and B of equal lengths as show in the figure . Cross-section area of A is half that of B and Young's modulus of A is double than that of B. A weight W is hung on the rod as shown. The value of x, so that the stress In A is same as that in B,is

Options

A. `(L)/(3)`
B. `(L)/(2)`
C. `(2L)/(3)`
D. `(3L)/(4)`

Answer

C

Explanation

Strees in `A = (T_(A))/(A_(A))`, where `A_(A)` is cross-sectional area of wire B.
It is given, `A_(A)=(A_(B))/(2),(T_(A))/(A_(A))= (T_(B))/(A_(B))` which gives x `=(2L)/(3)`