Home
Class 11
PHYSICS
Find the total elongation of the bar,...

Find the total elongation of the bar, if the bar is subjected to axical froces as shown in figure . The cross-section area of bar is `10 cm^(2)` .
`[Take E = 8 xx 10 ^(2) "dyne"//cm^(2)]`

A

0.01 cm

B

0.5 cm

C

0.0675 cm

D

0.775 cm

Text Solution

Verified by Experts

The correct Answer is:
C

Let `deltal`= total enlogation of the bar, A = area,
`E= 8 xx 10^(2)`. Let make the free body diagram .

Using equation `deltal= (1)/(AE)(F_(1)l_(1) + F_(2)l_(2) + F_(3)l_(3))`
`deltal =(1)/(10 xx 8 xx 10 ^(2))(5 xx 60 + 2 xx 60 + 1 xx120)`
`deltal=0.0675 cm`
Promotional Banner

Topper's Solved these Questions

  • ELASTICITY

    BITSAT GUIDE|Exercise BITSAT ARCHIVES|9 Videos
  • CIRCULAR MOTION

    BITSAT GUIDE|Exercise BITAST Archives|5 Videos
  • GRAVITATION

    BITSAT GUIDE|Exercise BITSAT Archives|15 Videos

Similar Questions

Explore conceptually related problems

A steel rod of cross-sectional area 1m^(2) is acted upon by forces as shown in the Fig. Determine the total elongation of the bar. Take Y = 2.0xx10^(11) N//m^(2)

A bar is subjected lu axial forces as shown. is the modulus of elasticity of the bar is E and A is it cross-section area. Its elongation will be

To double the length of a iron wire having 0.5 cm^(2) area of cross-section, the required force will be (Y = 10^(12) "dyne/cm"^(2))

the position vector of the centre of mass lt to r cm of an asymmetric uniform bar of negligible area of cross - section as shown in figure is :

Two short bar moment each 200 A-m^(2) are placed as shown in the figure at the corners of a square of side 10 cm.The magnetic induction at P is

Determine the elongation of the steel bar 1m long and 1.5 cm^(2) cross-sectional area when subjected to a pull of 1.5xx10^(4) N. (Take Y=2.0xx10^(11 )N//m^(2)) .

The magnetization of a bar magnet of length 5 cm,cross-sectional area 2 cm^(2) and magnetic moment 1 Am^(2) is

If a magnetising field of 1600 A//m produces a magnetic flux of 14xx10^(-5) Wb in an iron bar of cross-sectional area 0.2 cm^(2) . Then,

Two short bar magnets of moment each 100 A-m^(2) are placed as shown in figure at the corners of a square of side 10 cm.The magnetic induction at P is

Two bars are untressed and have lengths of 25cm and 30cm at 20^(@)C as shown in Figure. Bar (1) is of aluminium and bar (2) is of steel. The croos-sectional area of bars are 20cm^(2) for aluminium and 10cm^(2) for steel. Assuming that the top and bottom supports are rigid, stress in (N)/(mm^(2)) when the temperature is 70^(0)C . (Nearly) ( Y_(a)=0.70xx10^(5)N//mm^(2)Y_(s)=2.1xx10^(5)N//mm^(2).alpha_(a)=24xx10^(-6//0)C and alpha_(s)=12.xx10^(-6//0)C )