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Two wires one of copper and other of ste...

Two wires one of copper and other of steel having same cross-sectionl area end to end and strecteched by a load M. Ifcopper wire Is stretched by 1 mm, the total extnsion of the combined wire is
(Givwen, Young's are `Y_("copper")= 1 xx 10^(11) N//m^(2), and Y_("steel") = 2 xx 10^(11) N//m^(2))`

A

1.125 cm

B

0.2 cm

C

0.120 cm

D

0.25 cm

Text Solution

Verified by Experts

The correct Answer is:
A
`Deltal=(F)/(A)(l)/(Y)`
`(F)/(A)` is identical for the both the wire .
`(Deltal_(2)("copper"))/(Deltal_(2)("steel"))= (l_(1))/(Y_(1))(Y_(2))/(l_(2))`
`Deltal_(2)=Deltal_(1)(Y_(1))/(Y_(2)).(l_(2))/(l_(1))=(1)((0.5)/(1))((1 xx 10 ^(11))/(2 xx 10 ^(11))) = 0.25 cm`
Total extension = ` 1 + 0.25 = 1.125 mm`
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