For all real values of x, the minimum value of `(1-x+x^2)/(1+x+x^2)` is
(A) 0
(B) 1
(C) 3
(D) `1/3`

Explanation

To find the minimum value of the function \( y = \frac{1 - x + x^2}{1 + x + x^2} \), we will follow these steps:

### Step 1: Differentiate the function
We start by differentiating \( y \) with respect to \( x \).

\[ y = \frac{1 - x + x^2}{1 + x + x^2} \]
...