The angle turned by a body undergoing circular motion depends on time as `theta = theta_(0)+theta_(1)t+theta_(2)t^(2)`. Then the angular acceleration of the body is

Options

A. `theta_(1)`
B. `theta_(2)`
C. `2 theta_(1)`
D. `2 theta_(2)`

Answer

D

Explanation

Angle turned by the body,
`theta=theta_(0)+theta_(1)t+theta_(2)t^(2)`
Angular velocity, `omega=(d theta)/(dt)rArr(d)/(dt)(theta_(0)+theta_(1)t+theta_(2)t^(2))=theta_(1)+2 theta_(2)t`
Angular acceleration, `alpha=(d omega)/(dt)rArr (d)/(dt)(theta_(1)+2 theta_(2)t)2 theta_(2)`.