A particle is suspended from a fixed point by a string of lengh `5m`. It is projected from the equilibrium position with such a velocity that the string slakens after the particle has reached a height `8m` above lowest point. Find the velocity of the particle, just before the string slackens.
Find also, to what to what height the particle can rise further?

A particle is suspended from a fixed point by a string of lengh 5m It is projecte dfrom the equilibrium position with such a velocity that the string slakens after the particle has reached a height 8m above lower poinrtr. Find the velocity of the particle, just before the string slackens. Find also, to what to what heioght the particle can rise further?

A particle is suspended from a fixed point by a string of length 5m. It is projected from the equilibrium position with such a velocity that the string slackens after the particle has reached a height 8 m above the lowest point. Find the velocity of the particle, just before the string slackens. Find also, to what height the particle can rise further Take g=10 m//s^(2)

A particle of mass m is suspended from a fixed point O by a string length l.At t=0, it is displaced from its equilibrium position and released.If T is the tension in the string with time t, then the correct graph is

A particle of mass m is suspended from a fixed O by a string of length L. At t = 0 , it is displaced from its equilibrium position and released. The graph which shows the variation of the tension T in the string with time t is :

A particle suspended from a fixed point, by a light inextensible thread of length L is projected horizontally from its lowest position with velocity 7gL . The thread will slack after swinging through an angle , such that  equal

A particle suspended by a light inextensible thread of length l is projected horizontally from its lowest position with velocity sqrt(7gl//2) . The string will slack after swinging through an angle equal to

A heavy particle hangs from a point O, by a string of length a. It is projected horizontally with a velocity u = sqrt((2 + sqrt(3))ag) . The angle with the downward vertical, string makes where string becomes slack is :

A heavy particle is attached to one end of a string 1m long whose other end is fixed at O. It is projected from it lowest position horizontally with a velocity V:

A particle of mass m attached to a string of length l is descending circular motion on a smooth plane inclined at an angle alpha with the horizontal. For the particle to reach the highest point its velocity at the lowest point should exceed.