A heavy particle hanging from a fixed point by a light inextensible string of length l is projected horizontally with speed (gl) . Then the speed of the particle and the inclination of the string to the vertical at the instant of the motion when the tension in the string equal the weight of the particle-

A heavy particle hanging from a fixed point by a light inextensible string of length l is projected horizonally with speed sqrt(gl) . Find the speed of the particle and the inclination of the string to the vertical at the instant of the motion when the tension in the string is equal to the weight of the particle.

A heavy particle hanging from a string of length l is projected horizontally with speed sqrtgl . Find the speed of the particle at the point where the tension in the string equals weight of the particle.

A stone hanging from a massless string of length 15m is projected horizontally with speed sqrt(147) ms^(-1) Then the Speed of the particle, at the point where tension in string equals the weight of particle, is

The bob hanging from a light string is projected horizontally with a speed u_(0) . In the subsequent upward motion of the bob in vertically plane

A particle suspended from a fixed point, by a light inextensible thread of length L is projected horizontally from its lowest position with velocity 7gL . The thread will slack after swinging through an angle , such that  equal

A heavy particle hangs from a point O, by a string of length a. It is projected horizontally with a velocity u = sqrt((2 + sqrt(3))ag) . The angle with the downward vertical, string makes where string becomes slack is :

A particle is projected horizontally with a speed u from the top of plane inclined at an angle theta with the horizontal. How far from the point of projection will the particle strike the plane ?

A particle of mass m is tied to a string of length L and whirled into a horizontal plan. If tension in the string is T then the speed of the particle will be :