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The pressure inside a tyre is 4 atm at 2...

The pressure inside a tyre is 4 atm at `27^(@)C`.If the tyre bursts suddenly, its final temperature will be

A

`300(4)^(7)/(2)`

B

`300(4)^(2)/(7)`

C

`300(2)^(7)/(2)`

D

`300(4)^(-2)/(7)`

Text Solution

Verified by Experts

The correct Answer is:
D
In an adiabatic process,
`P_(2)^((1-gamma))T_(2)^(gamma) = P_(1)^((1-gamma))T_(1)^(gamma)`
`T_(2)=T_(1)(P_(1)/(P_(2))^((1-gamma))gamma = 300 (4/1)^((1-7//5))/(7//5)=300(4)^(-2//(7)`
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