Find both the maximum value and minimum value of
`3x^4-8x^3-48 x-25` on the interval [0, 3].

Explanation

To find both the maximum and minimum values of the function \( f(x) = 3x^4 - 8x^3 - 48x - 25 \) on the interval \([0, 3]\), we will follow these steps:

### Step 1: Find the derivative of the function
First, we need to find the derivative of the function \( f(x) \).

\[ f'(x) = \frac{d}{dx}(3x^4 - 8x^3 - 48x - 25) \]
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