A galvanic cell consists of two hydrogen electrodes. One is in a `1.0 M H^(+)` solution and other in a solution of unknown pH. The cell potential is 0.025V. The unknown pH is

Options

A. 0.52
B. 0.62
C. 0.42
D. 0.82

Answer

C

Explanation

`rArr Pt, H_(2)|H^(+) (?) ||H^(+) (1M)|H_(2),Pt E = 0.025`
`=- 0.059 log. ([H^(+)])/(1) =0.059 pH rArr pH = 0.42`