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Use the Standard Reduction Potentials given below to calculate `K_(f)` for `[Zn(NH_(3))_(4)]^(+2)` at `25^(@)`.
`Zn^(2+)(aq)+4NH_(3)(aq)ifZn(NH_(3))_(4)^(2+)(aq)`
`[Zn(NH_(3))_(4)]^(+2)+2e^(-)iffZn(s)+4NH_(3)(aq),`
`E^(@)=-1.04V , Zn^(2+)(aq)+2e^(-)iffZn(s),`
`E^(@)=-0.76V`

A

`6 xx 10^(18)`

B

`3 xx 10^(9)`

C

`2 xx 10^(6)`

D

`3 xx 10^(-9)`

Text Solution

Verified by Experts

The correct Answer is:
B
`E^(@)" for "Zn^(2+)(aq)+4NH_(3)(aq)+4NH_(3)(aq)`
`hArr[Zn(NH_(3))_(4)]^(+2)(aq)"is"0.28V`
Also, RT In `K_(f)=nE^(@)F=2xx0.28xx96500`
`rArr"In K"_(f)=(0.56xx96500)/(8.314xx298)=21.81`
`rArrK_(f)=3xx10^(9)`
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The EAN of Zn in [Zn(NH_(3))_(4)]^(2+) is

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