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The equilibrium constant for the reactio...

The equilibrium constant for the reaction Sr(s) `+Mg^(+2)(aq)rarrSr^(+2)(aq)+Mg(s)` is `2.69 xx 10^(12)` at `25^(@)C`. The `E^(o)` for a cell mad up of the `Sr//Sr^(+2)` and `Mg^(+2)//Mg` half cells

A

0.3667 V

B

0.7346 V

C

0.1836 V

D

0.1349 V

Text Solution

Verified by Experts

The correct Answer is:
A
`E^(@)=(0.059)/(2)log(2.96xx10^(12))`
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