How much electricity in terms of Faraday is required to produce `20 g` of `Ca` from molten `CaCl_(2)` ?

Options

A. 1.5
B. 2
C. 1
D. 4

Answer

C

Explanation

`"Eq. of Ca",(w)/(E)=(ixxt)/(96500),Ca^(2+)+2erarrCa`
`thereforeE_(Ca)=(40)/(2)or (20)/(40//2)=(ixxt)/(96500)`
`ixxt=1xx96500=1F`