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Electrode potential data are given below...

Electrode potential data are given below
`{:(Fe^(3+)(aq)+e^(-)rarrFe^(2+)(aq),E^(@)=+0.77V),(Al^(3+)(aq)+3e^(-)rarrAl(s),E^(@)=-1.66V),(Br_(2)(aq)+2e^(-)rarrBr^(-)(aq),E^(@)=+1.05V):}`
Based on the given data which statements is/are true?

A

`Fe^(2+)` is stronger reducing agent than `Br^(-)`

B

`Fe^(2+)` is stronger reducing agent than Al

C

Al is stronger reducing agent than `Fe^(2+)`

D

`Br^(-)` is stronger reducing agent than Al

Text Solution

Verified by Experts

The correct Answer is:
A, C
Based on electrochemical series
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Standard electrode potential data is given below : Fe^(3+) (aq) + e ^(-) rarr Fe^(2+) (aq) , E^(o) = + 0.77 V Al^(3+) (aq) + 3e^(-) rarr Al (s) , E^(o) = - 1.66 V Br_(2) (aq) + 2e^(-) rarr 2Br^(-) (aq) , E^(o) = +1.08 V Based on the data given above, reducing power of Fe^(2+) Al and Br^(-) will increase in the order :

Electrode potential data are given below: Fe^(3+)(aq)+e^(-)rarrFe^(2+)(aq):E^(@)=+0.77V Al^(3+)+3e^(-)rarrAl(s):E^(@)=-1.66V Br_(2)(aq)+2e^(-)rarr2Br^(-)(aq):E^(@)=+1.08V , Based on the data, the reducing power of Fe^(2+) Al and Br^(-) will increase in the order

Standard reduction potentials of the half reactions are given below {:(F_(2(g))+2e^(-) rarr 2F^(-)""_((aq)),,E^(@)=+2.85V), (Cl_(2(g))+2e^(-) rarr 2Cl^(-)""_((aq)),, E^(@)=+1.36V), (Br_(2(l))+2e^(-) rarr 2Br^(-)""_((aq)),,E^(@)=+1.06V), (l_(2(s))+2e^(-) rarr 2l^(-)""_((aq)),, E^(@)=+0.53V):} The strongest oxidising and reducing agents respectively are

Given : Fe^(2+)(aq)+2e^(-) rarr Fe(s), " "E^(c-)=-0.44V Al^(3)+3e^(-) rarr Al(s)," "E^(c-)=-1.66V Br^(2+)+2e^(-)rarr 2Br^(c-)(aq)" "E^(c-)=-1.08V The decreasing order of reducing power is ……………………………….. .

For the reduction of NO_(3)^(-) ion in an aqueous solution E^(@) is +0.96V . Value of E^(@) for some metal ions are given below V^(2+)(aq)+2e^(-)rarrV E^(@)=-1.19V Fe^(3+)(aq)+3e^(-)rarrFe E^(@)=-0.04V Au^(3+)(aq)+3e^(-)rarrAu E^(@)=+1.40V Hg^(2+)(aq)+2e^(-)rarrHg E^(@)=+0.86V The pair(s) of metal that is/are oxidised by NO_(3)^(-) in aqueous solution is(arE):

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