A hydrogen electrode is dipped in a solution at `25^(@)C`. The potential of cell is `-0.177 V`. Calcualte the `pH` of the solution.

Answer

C

Explanation

`E=E^(@)-(0.059)/(n)log.(1)/([H^(+)])`
`-0.177=0+(0.059)/(1)log[H^(+)]`
`log[H^(+)]=-3" "thereforepH=-log[H^(+)]=3`