A compund reacts with `CHCl_(3)` and `KOH` gives offensive smelling compound `A`. `'A'` can be

Options

A. Primary aliphatic amine
B. Primary aromatic amine
C. `2^(@)` amine
D. Tertiary amine

Explanation

To solve the problem, we need to identify the compound 'A' that is formed when a primary amine reacts with chloroform (CHCl₃) and potassium hydroxide (KOH). The reaction is known as the "Hofmann degradation" or "Hofmann reaction," which typically involves the formation of isocyanide (also known as carbylamine) from primary amines.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are chloroform (CHCl₃) and potassium hydroxide (KOH), which are used in the reaction with a primary amine.

2. **Understand the Reaction**:
- When a primary amine (RNH₂) reacts with chloroform and KOH, it undergoes a reaction to form an isocyanide (RNC), which is the offensive-smelling compound 'A'.

3. **Write the Reaction**:
- The general reaction can be represented as:
\[ RNH_2 + CHCl_3 + 3KOH \rightarrow RNC + 3KCl + 3H_2O \]
- Here, R represents the alkyl or aryl group attached to the amine.

4. **Identify the Product**:
- The product formed, isocyanide (RNC), is known for its offensive smell, which confirms that 'A' is indeed isocyanide.

5. **Conclusion**:
- Therefore, the offensive-smelling compound 'A' that is formed from the reaction of a primary amine with chloroform and KOH is an isocyanide.

### Final Answer:
The offensive-smelling compound 'A' is an isocyanide (RNC).