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Integrate the function xlog2x...

Integrate the function `xlog2x`

Text Solution

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Let `I=int xlog2xdx`
Taking `log2x` as first function and `x` as second function and integrating by parts, we obtain
`I=log2x intxdx-int{(d/dxlog2x)intxdx}dx`
=`log2x*x^2/2-int2/(2x)*(x^2)/2dt`
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