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Integrate the function x log x...

Integrate the function `x log x`

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Let `I=x log x`
Taking `logx` as the first and `x` as second function and integrating by parts, we obatin
`I= logx int xdx-int {(d/dxlogx)intxdx}dx `
`= logx*x^2/2-int1/x*x^2/2dx`
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