Column-1 gives three physical quantities. Select the appropriate units for the choices given in column-II. Some of the physical quantities may have more than one choice.
`{:("Column-I",,"Column-II"),("Capacitance",,"ohm-second"),("Inductance",,"Coulomb"^(2)//"Joule"),("Magnetic induction",,"coulomb"//"volt"),(,,"newton"//"ampere metre"),(,,"volt-second"//"ampere"):}`

Explanation

(I) `q=CV i.e., [C]=[q//V]` so `[C]=[M^(-1)L^(-2)T^(4)A^(2)]`
`U=1/2Li^(2), i.e., [L]=[U//i^(2)]` so `[L]=[ML^(2)T^(-2)A^(-2)]`
`F=Bil sin theta, i.e., [B]=[F//il]` so `[B]=[MT^(-2)A^(-1)]`
(II) Now the dimensions from given units are
`ohmxx sec equiv [R][T] rarr [ML^(2)T^(-3)A^(-2)][T]`
`=[ML^(2)T^(-2)A^(-2)]`
`"coul"^(2)-"joule"^(-1) equiv [q^(2)/W] rarr ([A^(2)T^(2)])/([ML^(2)T^(-2)])`
`=[M^(-1)L^(-2)T^(4)A^(2)]`
`"coul (volt)"^(-1) equiv[q^(2)/W] rarr ([A^(2)T^(2)])/([ML^(2)T^(-2)])=[M^(-1)L^(-1)T^(4)A^(2)]`
`"newton (amp-m)"^(-1) equiv [F/(il)] rarr ([MLT^(-2)])/([AL])=[MT^(-2)A^(-1)]`
`"volt sec (amp)"^(-1) equiv [(WxxT)/(qxxA)] rarr [(ML^(2)T^(-2)T)/(ATA)]`
`=[ML^(2)T^(-2)A^(-2)]`
Comparing dimensions of II with I, we find that :
Capacitance has unit `"coulomb"^(2)"-joule"^(-1)`, and coulomb `("volt")^(-1)`, inductance has units ohm-sec and volt-sec `("ampere")^(-1)`, and magnetic induction has unit newton `("ampere m")^(-1)`.