The frequency `f` of vibrations of a mass `m` suspended from a spring of spring constant `k` is given by `f = Cm^(x) k^(y)` , where `C` is a dimensionnless constant. The values of `x and y` are, respectively,

Answer

`x=-1/2, y=1/2`

Explanation

`f=cm^(x)k^(y)`
`[T^(-1)]=[M]^(x)[MT^(-2)]^(y)`
`y=1/2`
`x=-1/2`