In an experiment using post-office box, the resistance of a wire is found to be `(64 pm 1)` ohm. The length and radius of the wire are measured to be `(156.0 pm 0.1)` cm and `(0.26 pm 0.001)` cm. Calculate specific resistance (or resistivity) of the material of the given wire, within the limits of percentage error.

Explanation

Specific resistance, `rho=(pir^(2)R)/(l)=8.7xx10^(-4)` ohm metre
`(Delta rho)/rhoxx100=[2((Deltar)/r)+(DeltaR)/R+(Deltal)/l]xx100=2%`