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If L and R denote inductance and resista...

If L and R denote inductance and resistance respectively, then the dimension of `L//R` is :

A

`[M^(0)L^(0)T^(0)]`

B

`[M^(0)L^(0)T]`

C

`[M^(2)L^(0)T^(2)]`

D

`[MLT^(2)]`

Text Solution

AI Generated Solution

The correct Answer is:
To find the dimension of \( \frac{L}{R} \), where \( L \) is inductance and \( R \) is resistance, we will follow these steps: ### Step 1: Write the dimensions of inductance \( L \). Inductance \( L \) can be expressed in terms of energy \( U \) and current \( I \). The formula for energy stored in an inductor is given by: \[ U = \frac{1}{2} L I^2 \] From this, we can rearrange to find \( L \): \[ L = \frac{2U}{I^2} \] Now, we need the dimensions of \( U \) (energy) and \( I \) (current). The dimension of energy \( U \) is: \[ [M L^2 T^{-2}] \] The dimension of current \( I \) is: \[ [A] \] Thus, substituting these dimensions into the expression for \( L \): \[ \text{Dimension of } L = \frac{[M L^2 T^{-2}]}{[A^2]} = [M L^2 T^{-2} A^{-2}] \] ### Step 2: Write the dimensions of resistance \( R \). Resistance \( R \) is defined as: \[ R = \frac{V}{I} \] Where \( V \) (voltage) can be expressed in terms of work done \( W \) and charge \( Q \): \[ V = \frac{W}{Q} \] And since work \( W \) is energy, we have: \[ V = \frac{U}{Q} \] The dimension of charge \( Q \) is: \[ [I \cdot T] = [A \cdot T] \] Thus, the dimension of voltage \( V \) becomes: \[ \text{Dimension of } V = \frac{[M L^2 T^{-2}]}{[A \cdot T]} = [M L^2 T^{-3} A^{-1}] \] Now substituting this into the expression for \( R \): \[ \text{Dimension of } R = \frac{[M L^2 T^{-3} A^{-1}]}{[A]} = [M L^2 T^{-3} A^{-2}] \] ### Step 3: Calculate the dimensions of \( \frac{L}{R} \). Now, we can find the dimension of \( \frac{L}{R} \): \[ \frac{L}{R} = \frac{[M L^2 T^{-2} A^{-2}]}{[M L^2 T^{-3} A^{-2}]} \] When we divide these dimensions, we can cancel out the common terms: \[ = \frac{[M L^2 T^{-2} A^{-2}]}{[M L^2 T^{-3} A^{-2}]} = [T^{1}] \] Thus, the dimension of \( \frac{L}{R} \) is: \[ [M^0 L^0 T^1] = [T] \] ### Final Answer: The dimension of \( \frac{L}{R} \) is \( [T] \). ---
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