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Find the value of x in the relation Y ...

Find the value of x in the relation
`Y = (T^x . Cos theta. Tau)/(L^3), where`
Y is Young's modulu. T is time period, 'Tau' is torque and L is length.

A

zero

B

1

C

2

D

3

Text Solution

Verified by Experts

The correct Answer is:
a
Dimension of `(T^(x). Tau)/l^(3)=` Dimension of Y
Dimension of `T^(x)=("Dimension of Y"xx" Dimension of "l^(3))/("Dimension of "tau)`
`=([ML^(-1)T^(-2)][L^(3)])/([ML^(2)T^(-2)])`
`rArr" "x=0`
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